I have question on example 17 in the draft. $x = $a<1-> {$$}; $$ resolves to the last occurrence of $a. The effect is equivalent to $x = ($a {$$})<1->. I think there is one difference between the two rules. In the first one, {$$} only gets evaluated once when $x was matched. But in the second case, ($$) gets evaluated every time $a was matched. If we parse "111" using following grammars: 1. root $x; $a = '1'; $x = {$=""} $a<1-> {$+=$$}; 2. root $x; $a = '1'; $x = {$=""} ($a{$+=$$})<1-> ; I think the first one gives us $x="1", and the second one $x="111". Am I right? Jia (Jay) Pu Software Engineer LumenVox LLC ------------------------------------------- Anytime a linguist leaves the group the recognition rate goes up. --Fred Jelinek (then of the IBM speech group) (1988)Received on Thursday, 8 April 2004 16:44:20 GMT
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