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Re: [Fwd: [Moderator Action] Patterns broken in Adobe SVG Viewer 3.0 Beta 4?]

From: Jon Ferraiolo <jferraio@Adobe.COM>
Date: Tue, 27 Feb 2001 09:14:49 -0800
Message-Id: <4.2.2.20010227091218.01af4490@mailsj.corp.adobe.com>
To: Chris Lilley <chris@w3.org>
Cc: SVG public list <www-svg@w3.org>
The SVG specification changed with the Nov. 2, 2000 draft to make the 
default value for 'patternUnits' to be objectBoundingBox instead of 
userSpaceOnUse. The Adobe SVG Viewer 2.0 beta 4 matches this latest draft.

Because of this, defining the x/y/width/height to be 0/0/15/15 results in 
the pattern tile being 15 times as big as the referencing rectangle element.

To make it work, explicitly set patternUnits="userSpaceOnUse".

Jon Ferraiolo
SVG Editor
jferraio@adobe.com

At 05:13 PM 2/27/01 +0100, Chris Lilley wrote:
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>From: Petilon <petilon@yahoo.com>
>To: www-svg@w3.org
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>Subject: [Moderator Action] Patterns broken in Adobe SVG Viewer 3.0 Beta 4?
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>The following SVG file displays fine in IBM SVGView v0.4a.
>Adobe displays the rectangle but not the pattern.
>
>Is the SVG pattern below incorrect, or is Adobe's viewer broken?
>
><?xml version="1.0" standalone="no"?>
><svg width="150" height="100" viewBox="0 0 150 100">
><defs>
>   <pattern id="pat1" x="0" y="0" width="15" height="15">
>     <rect width="15" height="15" style="fill:white"/>
>     <path style="fill:none;stroke:black" d="M 0,7.5 L 15,7.5"/>
>   </pattern>
></defs>
><rect style="stroke:red;fill:url(#pat1)"
>    x="5" y="5" width="140" height="90"/>
></svg>
>
>
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Received on Tuesday, 27 February 2001 12:15:52 GMT

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