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Re: [selectors-nonelement] ::attr(*|localname), ::attr(ns|*), and ::attr(*)

From: Simon Sapin <simon.sapin@exyr.org>
Date: Mon, 24 Feb 2014 21:26:23 +0000
Message-ID: <530BB8FF.8010801@exyr.org>
To: "Tab Atkins Jr." <jackalmage@gmail.com>, Simon Pieters <simonp@opera.com>
CC: Jirka Kosek <jirka@kosek.cz>, www-style <www-style@w3.org>
On 24/02/2014 21:16, Tab Atkins Jr. wrote:
> In type selectors, "foo" and "*" are treated differently wrt
> namespaces when there's no default namespace.  "foo" is equivalent to
> "|foo", but "*" is equivalent to "*|*".

That is not the case.

http://dev.w3.org/csswg/selectors4/#typenmsp says:

E
     if no default namespace has been declared for selectors, this is 
equivalent to *|E. Otherwise it is equivalent to ns|E where ns is the 
default namespace.


> So consistency with attribute selectors is maintained - ::attr(foo)
> would select attributes in the null namespace, same as [foo], but
> ::attr(*) selects all attributes regardless of namespace.

-- 
Simon Sapin
Received on Monday, 24 February 2014 21:26:56 UTC

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