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RE: [css3-images] Changing the angles in gradients

From: Brian Manthos <brianman@microsoft.com>
Date: Wed, 18 May 2011 21:44:54 +0000
To: Tab Atkins Jr. <jackalmage@gmail.com>, www-style list <www-style@w3.org>, Robert O'Callahan <rocallahan@gmail.com>, Simon Fraser <smfr@me.com>
Message-ID: <FA122FEC823D524CB516E4E0374D9DCF1FAF4836@TK5EX14MBXC136.redmond.corp.microsoft.com>
v.1.9.3 removes the syntaxes that show the equivalent negative angled values from Examples IX and XI.

While you could argue that the (now) -180deg case for Example IX is uninteresting, I think it's worth keeping the negative-angled equivalent in Example XI.

Tab, can you add back the appropriate negative angle syntax to Example XI?

- Brian

> -----Original Message-----
> From: www-style-request@w3.org [mailto:www-style-request@w3.org] On
> Behalf Of Tab Atkins Jr.
> Sent: Wednesday, May 18, 2011 10:06 AM
> To: www-style list; Robert O'Callahan; Simon Fraser
> Subject: Re: [css3-images] Changing the angles in gradients
> On Tue, May 17, 2011 at 12:57 PM, Tab Atkins Jr. <jackalmage@gmail.com>
> wrote:
> > So, we have three choices:
> >
> > A) Keep the angles as they are, with 0deg=East and 90deg=North
> > B) Switch to screen-coord polar, with 0deg=East and 90deg=South
> > C) Switch to bearing angles, with 0deg=North and 90deg=East
> Based on the frankly overwhelming preference for C expressed in the
> various feedback channels, particularly the css3.info poll, I'll change the spec
> to use bearing angles.
> ~TJ

Received on Wednesday, 18 May 2011 21:45:23 UTC

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