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[css3-images] conical-gradient()?

From: Tab Atkins Jr. <jackalmage@gmail.com>
Date: Mon, 21 Mar 2011 11:43:39 -0700
Message-ID: <AANLkTiky1iLmW5OdLGSW+muXhBd5v55u2zo7Yz6U4wVm@mail.gmail.com>
To: www-style list <www-style@w3.org>, Lea Verou <leaverou@gmail.com>
On Mon, Mar 21, 2011 at 11:24 AM, Lea Verou <leaverou@gmail.com> wrote:
> On 21/3/11 20:11, Tab Atkins Jr. wrote:
>> The only amendment I'd make to the grammar would be that I'd need a
>> new<conical-color-stop>  or something that took an<angle>  rather than
>> a<length>  or<percentage>  (neither of which make sense here, I
>> think).
> Very good point about <length>, I totally forgot about it. Yes, an <angle>
> makes much more sense. However, I'm failing to see why a <percentage>
> doesn't. The way I was thinking about it, percentages would be directly
> converted to <angle>s, where 100% would be 360deg, 50% would be 180deg and
> so on. Yes, it seems redundant, but it could be convenient as a shortcut and
> many authors would expect them to work in conical gradients too I think.

Ah, yeah, <percentage> would work.  Never mind me, then.

Received on Monday, 21 March 2011 18:44:31 UTC

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