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RE: [CSS3 Values] referencing width or height explicitly

From: Brian Manthos <brianman@microsoft.com>
Date: Fri, 19 Aug 2011 19:33:57 +0000
To: Tab Atkins Jr. <jackalmage@gmail.com>
CC: "www-style@w3.org" <www-style@w3.org>
Message-ID: <9710FCC2E88860489239BE0308AC5D17125C02@TK5EX14MBXC264.redmond.corp.microsoft.com>
#  <number-multiplicative-expression> :=
#     <number-term> |
#     <length-multiplicative-expression> '/' <length-term> |
#     <length-multiplicative-expression> 'mod' <length-term>

<length-term> can't have units?

-----Original Message-----
From: Tab Atkins Jr. [mailto:jackalmage@gmail.com] 
Sent: Friday, August 19, 2011 10:59 AM
To: Brian Manthos
Cc: www-style@w3.org
Subject: Re: [CSS3 Values] referencing width or height explicitly

On Fri, Aug 19, 2011 at 10:45 AM, Brian Manthos <brianman@microsoft.com> wrote:
> http://www.w3.org/TR/css3-values/#calc

>
> Is there a way to reference both width and height of the associated element
> explicitly via calc()?
>
> If not, can we add it to the proposal list for CSS4 Values?
>
> Having such support would allow more flexible specification of properties
> (such as gradients) that are sensitive to aspect ratio.  In retrospect,
> aspect ratio would be enough to solve some of the scenarios, but having
> width and height (and doing division within the calc when you want aspect
> ratio) is much more powerful.

In general, allowing this exposes circularity problems.  You really
want to expose this explicitly as an aspect ratio, via something like
the aspect-ratio property I have written up on my blog:
<http://www.xanthir.com/blog/b4810>.

Even if there were "element width" and "element height" units, you
couldn't use them in calc() to do things aspect-ratio related, because
you can't divide by a dimension.

> [Sidenote: “W3C Working Draft 19 September 2006”..  eep!]

Yeah, why do you think Fantasai and I are trying to get it updated?  ^_^

~TJ

Received on Friday, 19 August 2011 19:34:36 GMT

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