Re: border-radius

On Sep 4, 2008, at 12:34 AM, Nick_Hofstede@inventivegroup.com wrote:

>
> >> The proposed "innermost radius wins" rule doesn't have this problem
> >> in addition to being consistent with the color rule.
>
> > So far, the innermost radius is zero. Are you saying that if the TD
> > has a zero radius and the table has a non-zero radius, that the zero
> > should always win because it is smaller?
> >
> > I think the largest should win.
>
> No, with "innermost radius wins", I mean that the radius of the cell  
> should win.

Understood. But that means if the cell has zero radius and the table  
(or tbody or tr) has a large radius, that the cell wins, and there is  
no corner radii at all. Because no radius = border-radius:0.


> Let the largest (or smallest) radius win is another rule we should  
> consider.
>
> Nick
>
>
> Inventive Designers' Email Disclaimer:
> http://www.inventivedesigners.com/email-disclaimer
>
>
>
> -- 
> This message has been scanned for viruses and
> dangerous content, and is believed to be clean.
> --