Re: border-radius

On Sep 3, 2008, at 9:25 AM, Nick_Hofstede@inventivegroup.com wrote:

> The proposed "innermost radius wins" rule doesn't have this problem  
> in addition to being consistent with the color rule.

So far, the innermost radius is zero. Are you saying that if the TD  
has a zero radius and the table has a non-zero radius, that the zero  
should always win because it is smaller?

I think the largest should win.