On Sep 3, 2008, at 9:25 AM, Nick_Hofstede@inventivegroup.com wrote: > The proposed "innermost radius wins" rule doesn't have this problem > in addition to being consistent with the color rule. So far, the innermost radius is zero. Are you saying that if the TD has a zero radius and the table has a non-zero radius, that the zero should always win because it is smaller? I think the largest should win.Received on Wednesday, 3 September 2008 16:45:15 GMT
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