From: Brad Kemper <brkemper@comcast.net>

Date: Thu, 13 Mar 2008 10:54:02 -0700

Message-Id: <90C37DB0-E9CE-4EF1-B0C7-767BE54265CC@comcast.net>

Cc: www-style Mailing List <www-style@w3.org>

To: Christoph Päper <christoph.paeper@crissov.de>

Date: Thu, 13 Mar 2008 10:54:02 -0700

Message-Id: <90C37DB0-E9CE-4EF1-B0C7-767BE54265CC@comcast.net>

Cc: www-style Mailing List <www-style@w3.org>

To: Christoph Päper <christoph.paeper@crissov.de>

On Mar 12, 2008, at 8:55 AM, Brad Kemper wrote: > [...] This really is a mathematical formula, where "n" is the > progressively larger number representing the number of times > repeated so far, starting with zero and increasing by one with each > iteration (when using "+"). For each value of "n", solving the > formula tells you which child number to apply the style to. [...] > > I think the spec is not really that clear on the fact that this > really is a mathematical formula in which n = {0,1,2,3,4...}, where > solving the equation gives you the child number (assuming the child > elements are numbered starting with 1). It never really comes out > and says it that explicitly, even though it gives examples where > a=1 or b=0 or a is negative, etc. and the math continues to work. One thing that seems very wrong with the spec is this part; :nth-child(10n-1) /* represents the 9th, 19th, 29th, etc, element */ :nth-child(10n+9) /* Same */ In other words, if b is negative then b = (a + b) (the negative b is added to a, thus reducing it by the absolute value of b; this now positive value is then substituted for the previously negative value in the equation) . To my way of thinking, the two rules shown above should not be the same. Let me explain... For all the other examples given for nth-child, the following all works out beautifully: given (using existing (an+b) convention): a = multiplier for "n". Absolute value of which is the "grouping size" of which only one element of the group receives the style of the rule b = ordinal number of the child element within each "a" group that receives the style of the rule n = set of integers starting with 0, inserted into the formula one integer at a time, stopping when there are no remaining elements. c = total number of child elements t = total number of child elements that receives the style of the rule i = ignored solutions of equation after solving for the "n" values (where the equation equals a negative number or zero, since they repressent child element ordinal numbers that are not in the document tree) then: an-b = set of numbers representing ordinal identification of child elements t = c / abs(a) - (number of "i" values) So if you imagine a 12 row table, then the following is true given the selectors shown (and agrees with the spec): tr:nth-child(2n+1) { color: red; } number of rows colored red (t) = 12 / 2 red row numbers = 2 * { 0,1,2,3,4,5... } + 1 red row numbers = { 0,2,4,6,8,10 } + 1 red row numbers = { 1,3,5,7,9,11 } t = 6 red rows tr:nth-child(4n+1) { color: green; } number of rows colored green (t) = 12 / 4 green row numbers = 4 * { 0,1,2,3,4,5... } + 1 green row numbers = { 0,4,8 } + 1 green row numbers = { 1,5,9 } t = 3 green rows tr:nth-child(-n+6) { color: blue; } number of rows colored blue (t) = 12 / 1 blue row numbers = -1 * { 0,1,2,3,4,5... } + 6 blue row numbers = { 0,-1,-2,-3,-4,-5 } + 6 blue row numbers = { 6,5,4,3,2,1 } t = 6 blue rows However: tr:nth-child(4n-1) { color: orange; } number of rows colored orange (t) = 12 / 4 orange row numbers = 4 * { 0,1,2,3... } - 1 orange row numbers = { 0,4,8,12 } - 1 orange row numbers = { -1,3,7,11 } orange row numbers = { 3,7,11 } (nonsense values removed) t = 3 orange rows Not the same as: tr:nth-child(4n+3) { color: orange; } number of rows colored orange (t) = 12 / 4 orange row numbers = 4 * { 0,1,2,3... } +3 orange row numbers = { 0,4,8,12 } +3 orange row numbers = { 3,7,11,12 } t = 4 orange rows Thus: Having a negative "b" value could add power to the spec by letting you style all but the last 1 or more child elements. This would also make the math more sensible, and lead to an easier time for JavaScript to be able to determine which rows received the style. I see no upside to having this single part of the spec deviate from mathematical perfection.Received on Thursday, 13 March 2008 17:54:45 UTC

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