Re: [css3-fonts] Nested 'bolder' and 'lighter' question

fantasai wrote:
> 
> The spec isn't clear on what exactly happens here, so the CSSWG
> decided to ask web designers what they expect. So far I have two
> responses and they don't match. Anyone else have an opinion? :)
> 
> fantasai wrote:
>> Given
>>
>>   <a>
>>     Text A
>>     <b style="font-weight: bolder">
>>       Text B
>>       <c style="font-weight: bolder">
>>         Text C
>>         <d style="font-weight: lighter">
>>           Text D
>>         </d>
>>       </c>
>>     </b>
>>   </a>
>>
>> If you have three different weights in your font (normal, bold,
>> extra-bold) then
>>   - Text A will be normal
>>   - Text B will be bold
>>   - Text C will be extra-bold
>>   - Text D will be bold
>>
>> If you have only two weights in your font (normal, bold) then
>>   - Text A will be normal
>>   - Text B will be bold
>>   - Text C will be bold
>>
>> What should Text D be? Bold or normal?
> 
> I would say bold, if I were being so bold. -- Andy Clarke
> 
> I say it goes to normal. -- Molly Holzschlag

Mathematically speaking, I think of it like this:
normal = 0, bolder = +1, lighter = -1
So, bold values:
A = 0, B = 1, C = 2, D = 1

D is bold, in both cases.

With a two-weight font, it must be assumed that anything with a value
greater than 0 must be bold, 0 or lower is normal. The assumption has to
be that if the author wanted normal (0), s/he would have specified a
reset, or normal.

It's the reverse of this argument:
<a>Text A
  <b style="font-weight: lighter">Text B (-1)
    <c style="font-weight: lighter">Text C (-2)
      <d style="font-weight: bolder">Text D (-1)
      </d>
    </c>
  </b>
</a>

D would have to be normal in this case, not bold.

If no options existed for setting bold or normal, I would agree that
bolder=bold and that lighter=normal, but since there are options for
setting those values, I don't see how one can extrapolate any other
meaning for the author than by using the math.

Or am I missing something completely?



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