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Re: AW: WG: Cases in the new specification of RDF Schema

From: Chris Dollin <kers@hplb.hpl.hp.com>
Date: Fri, 11 Jun 2004 11:57:27 +0100
To: <www-rdf-interest@w3.org>
Message-Id: <200406111157.27607.kers@hplb.hpl.hp.com>

On Friday 11 June 2004 11:44, Kianoush Eshaghi wrote:

[Big quote]

> > On Friday 11 June 2004 11:13, Kianoush Eshaghi wrote:
> > > > 2. A Property would own multiple domains and rangs. It
> >
> > would like such
> >
> > > > as following:
> > > >
> > > > <rdf:Property rdf:about="a">
> > > > 	<rdfs:domain rdf:resource="#A"/>
> > > > 	<rdfs:range    rdf:resource="#B"/>
> > > > 	<rdfs:domain rdf:resource="#C"/>
> > > > 	<rdfs:range    rdf:resource="#D"/>
> > > > 	...
> > > > 	...
> > > > </rdf:Property>
> > >
> > > And this, but it probably doesnt mean what you think it
> >
> > does. It would
> >
> > > make anything that was in the domain of 'a' a member of #A and #C.
> > >
> > > My RDF Schema should assert that the domain of 'a' must contain only
> > > members of #A and #C, and the range of 'a' must contain
> >
> > only members of
> >
> > > #B and #D.
> >
> > And therefore if you find a triple
> >
> >     froglegs a smokechain
> >
> > you may deduce that froglegs has types A and C and that smokechain has
> > types B and D.
> >
> > Right?
>
> froglegs must have members with types of 'A' OR types of 'C'.
> smokechain must have members with types of 'B' OR types of 'D'.

As far as I understand it, to do that you'll have to make the range of
a be a union of A and C, and the domain be union of B and D.

-- 
Chris "electric hedgehog" Dollin
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Received on Friday, 11 June 2004 07:26:48 GMT

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