I mistakenly wrote: > Open Issues > horst-01 > does not seem to be addressed ... having read the comments list I will reproduce the proof. >>Consider the RDF graph G: >> x rdf:type rdfs:Class . (1) >> rdf:type rdfs:domain y . (2) rdf:type rdf:type rdf:Property . (3 = 1 and rdf1) rdf:type rdf:subPropertyOf rdf:type . (4 = 3 and rdfs5b) rdfs:Resource rdfs:subClassOf y. (5 = 2,4, and 12a) x rdfs:subClassOf rdfs:Rersource . (6 = 1 rdfs7a) >> x rdfs:subClassOf y . (7 = 5, 6, rdfs8) and the issue is addressed by the current editors draft. JeremyReceived on Wednesday, 18 June 2003 15:05:49 EDT
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