Graham Klyne wrote: [...] > So I think the above statement is either True or False, depending on the > interpretation used. So far, so good. But is this an RDFS-entailment: > > ex:s ex:p "foo"^^ddd . > |= > ex:s ex:p _:b . > _:b rdf:type rdfs:Literal . > > Intuitively, I would have said "yes", but as far as I can tell from the > semantics spec, the answer is "no". This is an entailment only in a > {RDFS,ddd}-interpretation, because it is only a D-interpretation that > places the required constraints on the relationships between > I(rdfs:Literal), LV and IL. > > Am I correct? Is this what we expected? As I recall, the way we handle datatype errors, i.e. where "foo" is not in the lexical space of ddd, is to say that "foo"^^ddd is not a member of rdfs:Literal. Therefore it is only appropriate datatype interpretations that can make this entailment. BrianReceived on Tuesday, 16 December 2003 05:27:31 EST
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