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Re: PL: how a perl programmer might do datatypes in RDF

From: Graham Klyne <Graham.Klyne@MIMEsweeper.com>
Date: Thu, 06 Dec 2001 18:51:00 +0000
Message-Id: <5.1.0.14.2.20011206184506.03304170@joy.songbird.com>
To: Dan Connolly <connolly@w3.org>
Cc: w3c-rdfcore-wg@w3.org
Dan,

I think that's a reasonable and consistent answer, but I'll note that's not 
what Perl does.
The following script:

#!/local/bin/perl
$a="10";
$b="010";
$c=10;
if ( $a==$b )
     {
     print "Equal '$a', '$b', '$c'\n";
     }
else
     {
     print "Not equal '$a', '$b', '$c'\n";
     }

prints:
     Equal '10', '010', '10'

I suppose that you could argue that '==' invokes a higher level of 
interpretation.

#g
--

At 10:50 AM 12/6/01 -0600, Dan Connolly wrote:
> > I think the issue of "10" vs "010" needs to be clear -- you seem to be
> > proposing that these ares distinct scalar values.
>
>yes; they are distinguishable in all interpretations.
>
> >  But under what
> > conditions does:
> >
> >      X foo "10" .
> >
> > entail
> >
> >      X foo "010" .
> >
> > ?
>
>it never RDF-entials nor RDFs-entials.
>
>However, in stuff layered on top of RDF/RDFS,
>if you added more axioms about foo... say, that
>         ?x foo ?a
>         ?a sameNumber ?b
>implies
>         ?x foo ?b
>then you would get that conclusion.

------------------------------------------------------------
Graham Klyne                    MIMEsweeper Group
Strategic Research              <http://www.mimesweeper.com>
<Graham.Klyne@MIMEsweeper.com>
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Received on Friday, 7 December 2001 00:41:30 EST

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