RE: Arrow operator and ParenthesizedExpr

> 
> Given a UnaryExpr U, an ArrowFunctionSpecifier F, and a ArgumentList (A, B,
> C…), the expression U => F(A, B, C…) is equivalent to the expression F(U, A,
> B, C…)
> 

That would work, or, if we were to allow the example I gave, this could be written as:

Given a UnaryExpr U, an ArrowFunctionSpecifier F, and a ArgumentList (A, B, C…), the expression U => F(A, B, C…) is ...

Is equiv. to the expression: for $f in F return $f(U, A, B, C...)

Cheers,
Abel

Received on Thursday, 10 September 2015 16:26:32 UTC