- From: Boris Zbarsky <bzbarsky@MIT.EDU>
- Date: Wed, 09 May 2012 21:10:54 -0400
- To: Nat Duca <nduca@google.com>
- CC: Yehuda Katz <yehuda.katz@jquery.com>, Jatinder Mann <jmann@microsoft.com>, "public-web-perf@w3.org" <public-web-perf@w3.org>
On 5/9/12 8:39 PM, Nat Duca wrote: > What do you set it to when you've been idle for a while? The last tick > may be many seconds ago. What Gecko's mozAnimationStartTime does is the following: 1) If there is no active animation timer, start one and set the "last tick" time to now. 2) Return the "last tick" time. And of course every tick sets the "last tick" time to the time when it happened. > So, I still claim that this is correct. It's "correct" only if your animation doesn't need to coordinate its start with other animations. If you want to start several animations, then setting each one's startTime based on the now() value when running its start code will put them slightly out of sync with each other. >>> var a= new Animation(1000.0); >>> a.addEventListener('animationEnded', function() { >>> assert(window.performance.now() - a.startTime>= a.duration); >>> aEnded = true; >>> checkBothEnded(); >>> }); >>> var b= new Animation(1000.0); >>> b.addEventListener('animationEnded', function() { >>> assert(window.performance.now() - b.startTime>= b.duration); >>> bEnded = true; >>> checkBothEnded(); >>> }); >>> checkBothEnded() { >>> if (!checkTaskEnqueued) window.postTask(checkBothEnded); > checkTaskEnqueued = true; > > Oops. :) > >>> assert (aEnded&& bEnded); >>> } I must still be missing something here... > The point is, if you use window.performance.now() to determine whether > an animation ended, and you have two animations that are ending at > exactly the same time, and the tick happens right on that boundary, > you can get one animation that ended and one animation that didn't > end. Yes, agreed.... That's because using window.performance.now() for _anything_ like boundary determination that way you will get screwed. If you use it for a _single_ animation it can fail in the same way if you happen to call now() twice! >> So in terms of rAF, "present time" would be the animation sample time and >> "frame begin time" would be the time it was before all the code for this >> frame started running? > > Sorry, I wasn't precise about definitions. In my notes, "present time" > uses the directx term for Present. That was stupid --- present meant > the time that the content will be visible to the user. Oh! Stress on _second_ syllable, not first syllable! That makes a rather large difference. ;) >> This looks like it's passing in an "inOutputTime" which is the animation >> sample time and the "inNow" which is .. not really all that well-defined. >> Is the same for different output callbacks, or does it increment? > > inNow goes up every frame, and is very close to the current system time. > inOutputTime is the time that that any rendered content is going to be > visible to the user. OK. But for a single frame inNow is the same for all callbacks triggered for that frame, right? It sounds like inNow is basically what Gecko passes in right now, and inOutputTime is what we'd like to pass in... Maybe it does make sense to pass in both. -Boris
Received on Thursday, 10 May 2012 01:11:25 UTC