Re: [SKOS] SKOS-XL & label relations

On 2 May 2008, at 11:04, Alistair Miles wrote:

>
> Hi Quentin,
>
> Yes, in a sense there is duplication. But XL gives you a convenient  
> way to
> make statements about the lexical entities used in a knowledge  
> organisation
> system, which vanilla SKOS doesn't. It also gives you a way to  
> "dumb-down"
> to vanilla SKOS, to get the simplified representation.
>
> E.g. using SKOS+XL ...
>
> <C1> rdf:type skos:Concept;
>   xl:prefLabel <L1>;
>   xl:altLabel <L2>;
>   skos:inScheme <S>.
>
> <L1> rdf:type xl:Label;
>   xl:literalForm "animals"@en;
>   skos:inScheme <S>;
>   dc:source "Another thesaurus."@en.
>
> <L2> rdf:type xl:Label;
>   xl:literalForm "fauna"@en;
>   skos:inScheme <S>;
>   dc:source "Yet another thesaurus."@en.
>
> ... which can be "dumbed-down" via the XL data model to vanilla  
> SKOS as ...
>
> <C1> rdf:type skos:Concept;
>   skos:prefLabel "animals"@en;
>   skos:altLabel "fauna"@en;
>   skos:inScheme <S>.
>
> ... does that make sense?
>
> I suppose you could achieve the same goal without xl:prefLabel,  
> xl:altLabel
> and xl:hiddenLabel, e.g. ...
>
> <C1> rdf:type skos:Concept;
>   xl:prefLabel "animals"@en;
>   xl:altLabel "fauna"@en;

Shouldn't these be skos:prefLabel and skos:altLabel?

>   skos:inScheme <S>.
>
> <L1> rdf:type xl:Label;
>   xl:literalForm "animals"@en;
>   skos:inScheme <S>;
>   dc:source "Another thesaurus."@en.
>
> <L2> rdf:type xl:Label;
>   xl:literalForm "fauna"@en;
>   skos:inScheme <S>;
>   dc:source "Yet another thesaurus."@en.

--
Sean Bechhofer
School of Computer Science
University of Manchester
sean.bechhofer@manchester.ac.uk
http://www.cs.manchester.ac.uk/people/bechhofer