- From: Richard Newman <rnewman@franz.com>
- Date: Tue, 10 Apr 2007 19:11:13 -0700
- To: "Cristina Lancioni, Doctor in Computer Science" <cristina.lancioni@unicam.it>
- Cc: public-sparql-dev@w3.org
> How could I do this using only a single query? Shoud I do this with > SPARQL? If not, do You know another ontology query language to do > this? SPARQL can't do arbitrary path expressions. Look at: http://psparql.inrialpes.fr/ for an extension that can. You might also want to look at the path expressions offered by WQL: http://wilbur-rdf.sourceforge.net/2004/05/11-comparison.shtml or at running your queries on an inferencing store, if your is-a relationships are transitive. > Another question: what do the CONSTRUCT work? Sorry, you'll have to rephrase that.
Received on Wednesday, 11 April 2007 02:11:22 UTC