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Re: More on MINUS vs. UNSAID

From: Eric Prud'hommeaux <eric@w3.org>
Date: Wed, 8 Jul 2009 12:58:30 -0400
To: Lee Feigenbaum <lee@thefigtrees.net>
Cc: SPARQL Working Group <public-rdf-dawg@w3.org>
Message-ID: <20090708165830.GD24527@w3.org>
* Lee Feigenbaum <lee@thefigtrees.net> [2009-07-08 01:13-0400]
> On yesterday's call, we spent a lot of time trying to understand the  
> differences between MINUS and UNSAID.
> I'm using this email to try to bring things together for myself, with  
> the help that one or more of the following will happen:
> a) it will help someone else similarly
> b) others will point out where i'm wrong
> c) if i understand it i'll be able to help explain it to others
> d) if i understand it i'll be able to formulate an informed opinion
> I'll start with MINUS, since we actually spent more time on that in  
> today's call. On the call, we came up with 3 potential definitions of  
> MINUS, which I'll recap here.
> In general, MINUS is a binary operation between solution sets. I use A  
> to represent the left-hand side (LHS) solution set of the MINUS operator  
> and B to represent the right-hand side solution set. In all cases, the  
> result of MINUS is always a (improper) subset of A -- the three  
> definitions differ in how to determine whether a particular solution  
> within A is retained or not.
> == MINUS-Set ==
> This was -- possibly erroneously -- called the SQL definition of MINUS  
> on the call. The idea is that it's a strict set difference operation --  
> a solution is removed from A only if that exact solution (same exact  
> bindings, no more & no less) occurs within B. There may be a slightly  
> looser version of this in which a solution is removed from A if that  
> solution is a subset of a solution in B.
> I'm guessing that the cardinality here is preserved - i.e., this would  
> really be multiset difference.

Let's assume that *our* MINUS is multiset, for consistency with our
UNION (which is analogous to SQL's UNION ALL). Most of SQL defaults
to preserving cardinality, apart from UNION and MINUS.

> There was some confusion on the call as to whether this is or is not  
> what SQL does with MINUS (which is confused further, I think, by the  
> fact that SQL acts over positional columns rather than named columns  
> (variables)?). In either case, I don't think I heard *any* support for  
> this definition of MINUS.

I do not support this definition.
More specifically, I support conceptual compatibility with SQL MINUS
modulo adapting it to SPARQL's preservation of cardinality and the
fact that in SPARQL, you can have no common variables in A and B.
Your MINUS-AntiJoin+Restriction choice is thus more applicable.

> == MINUS-AntiJoin ==
> This relies on the standard SPARQL join criteria to determine which  
> solutions to remove - i.e. any solution in A that could successfully  
> join with at least one solution B is instead removed from A.
> SPARQL defines the notion of "compatible mappings" (see  
> http://www.w3.org/TR/rdf-sparql-query/#BasicGraphPattern) -- two  
> solutions s1 and s2 are compatible if for every variable they share (in  
> their domain of bound variables), that variable is bound to the same  
> value in both s1 and s2. Note that this means that two solutions that  
> share no variables in common are (vacuously) compatible.
> SPARQL joins are defined in terms of compatible mappings - the result of  
> Join(A, B) is the merge (effectively union) of all pairs of compatible  
> solutions from A and B.
> So this definition of MINUS, then, says that A MINUS B removes from A  
> all of the solutions that are compatible with at least one solution in B.
> I'm not sure what MINUS does with the cardinality here...
> This definition has one oddity that leads to the third definition. If  
> (?a = "a") is a solution in A and there is a solution in B that doesn't  
> bind ?a, then this solution is removed from A (because of the vacuous  
> compatibility mentioned above). That is, MINUS-AntiJoin removes from A  
> any solution s_A for which there is a solution in B that shares no  
> variables in common s_A. This seems weird, but is a natural consequence  
> of this definition.
> I'm not sure if anyone on the call was advocating this definition.
> == MINUS-AntiJoin+Restriction ==
> This definition is like the previous, but adds the condition that a  
> solution s_A is only removed from A if there is a solution s_ B in B  
> such that s_A and s_B are compatible AND share at least one bound  
> variable in common. That is, to remove a solution from A,  
> MINUS-AntiJoin+Restriction requires there to be a solution in B that is  
> non-vacuously compatible with it.
> This seemed to be the definition that most of the proponents of MINUS on  
> the call advocated. Other members of the group were uncomfortable with  
> what seems to them to be an artificial restriction in the definition.
> OK, with this spelled out, I wanted to look at Eric's treatment in  
> http://lists.w3.org/Archives/Public/public-rdf-dawg/2009JulSep/0022.html. 
>   In particular, looking at this example in Eric's mail:
> """
> Query M3:
> ?who foaf:givenname ?name
>   ?who foaf:holdsAccount ?act
>     ?act foaf:accountName ?name .
>   }
> }
> Result M3:
> ?who   ?name    ?who   ?act   ?name    ?who   ?name
> _:eric "eric"   _:eric <act1> "eric"   _:bobS "bob"
> _:bobS "bob"  - _:bobS <act2> "bobS" = _:eve  "eve"
> _:eve  "eve"    _:eve  <act3>	
> """
> The only way that I can see that (?who=_:eve, ?name="eve") is retained  
> in the result of the MINUS is if Eric is using the "looser" form of the  
> MINUS-set definition that I give above. Eric, can you confirm this is  
> the case? The two MINUS-AntiJoin* definitions would, I think, eliminate  
> that solution because (?who=_:eve, ?name="eve") is compatible with  
> (?who=_:eve, ?act=<act3>).

I think you've made a leap from "AND share at least one bound
variable" to "have any variables in common". As I understand both
MINUS-AntiJoin and MINUS-AntiJoin+Restriction, both restrict A if
there is a tuple in B with the same values for all the bindings.
Thus, a distinguishing test case for these would be:

?who foaf:givenname ?name
  ?who2 foaf:holdsAccount ?act
    ?act foaf:accountName ?name2 .

> ...I'm going to punt on UNSAID tonight because it's getting late and I  
> don't have an easy way to explain it. Andy explains it as a !EXISTS  
> filter (i.e., solve A and then for each solution in A, filter it against  
> a !EXISTS filter) - but without totally understanding what !EXISTS  
> means, I can't really see how that relates to these MINUS definitions.
> Greg (& someone else?) explained UNSAID today as AntiOptional. I'm  
> wondering if "AntiOptional" is actually the same as  
> MINUS-AntiJoin+Restriction? Can anyone tell?
> Lee


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Received on Wednesday, 8 July 2009 16:59:14 UTC

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