- From: Jos De_Roo <jos.deroo@agfa.com>
- Date: Sat, 18 Sep 2004 21:27:16 +0200
- To: "Steve Harris <S.W.Harris" <S.W.Harris@ecs.soton.ac.uk>
- Cc: public-rdf-dawg@w3.org, public-rdf-dawg-request@w3.org
SteveH wrote:
> On Fri, Sep 17, 2004 at 02:42:37AM -0700, Rob Shearer wrote:
>>
>> A user wishes to find all the people who are either of type
>> dog owner or own a pet who is a dog. (In the common case of
>> no inferencing this is a pretty realistic query.)
>> Some sample data:
>>
>> Rob type Person
>> Eddie type Person
>> Eddie type DogOwner
>> Mitch type Person
>> Mitch hasPet Fido
>> Fido type Dog
>>
>> query
>>
>> select $x
>> where ($x type Person)
>> (($x type DogOwner) OR
>> (($x hasPet $y) ($y type Dog))
>>
>> Is this query correct?
>
> Looks good to me, an OPTIONAL equivalent would be:
>
> SELECT $x
> WHERE ($x type Person)
> OPTIONAL ($x type $typeA)
> OPTIONAL ($x hasPet $y) ($y type $typeB)
> AND $typeA = DogOwner || $typeB == Dog
>
> [OT note] I found using $'s for this query quite distracting.
:)
Using a capability for multiple queries in the same request
that would simply be
SELECT ?X
WHERE {?X a :Person . ?X a :DogOwner}
SELECT ?X
WHERE {?X a :Person . ?X :hasPet ?Y . ?Y a :Dog}
returning
(:Eddie) a q:Answer.
(:Mitch) a q:Answer.
--
Jos De Roo, AGFA http://www.agfa.com/w3c/jdroo/
Received on Saturday, 18 September 2004 19:27:59 UTC