[Bug 17600] Range predicates

https://www.w3.org/Bugs/Public/show_bug.cgi?id=17600

--- Comment #8 from John Snelson <john.snelson@marklogic.com> 2012-06-26 16:00:54 UTC ---
(In reply to comment #7)
> Surely not? It depends on the type of PRED, rather than the type of $s. It must
> be something like this:
> 
> for $s at $p in SEQ
> where
>   typeswitch($s/(PRED))
>   case op:numeric+ return $p = $s/(PRED)
>   default return fn:boolean($s/(PRED))
> return $s

Err, yes - that was a mistake.

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Received on Tuesday, 26 June 2012 16:01:04 UTC