[Bug 3759] [F+O] round-half-to-even and float precision

http://www.w3.org/Bugs/Public/show_bug.cgi?id=3759





------- Comment #1 from ashok.malhotra@oracle.com  2006-09-27 22:29 -------
I'm not sure what to do abt this.  I understand both Mike and Joanne's
arguments.
The summary of the function currently says "The value returned is the nearest
(that is, numerically closest) value to $arg that is a multiple of ten to the
power of minus $precision. If two such values are equally near (e.g. if the
fractional part in $arg is exactly .500...), returns the one whose least
significant digit is even."

Would it help to add something like "floating point numbers are compared using
a decimal representation"?  But then we need to say something abt the number of
decimal places.