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[Bug 1588] New: [FS] editorial: 4.2.1 Steps

From: <bugzilla@wiggum.w3.org>
Date: Thu, 14 Jul 2005 06:01:23 +0000
To: public-qt-comments@w3.org
Cc:
Message-Id: <E1Dswmh-0000KP-UQ@wiggum.w3.org>

http://www.w3.org/Bugs/Public/show_bug.cgi?id=1588

           Summary: [FS] editorial: 4.2.1 Steps
           Product: XPath / XQuery / XSLT
           Version: Last Call drafts
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: Formal Semantics
        AssignedTo: simeon@us.ibm.com
        ReportedBy: jmdyck@ibiblio.org
         QAContact: public-qt-comments@w3.org


4.2.1 Steps

Introduction
[81 (XQuery)] PredicateList ::= Predicate*
    The Normalization rules assume a left-recursive definition, such as:
        ... ::= | PredicateList Predicate

Norm / rule (1|2|3|4|5|6)
"[" Expr "]"
    Delete quotes around square brackets.

Norm / rule (1|3)
"[" Numeric "]"
    Change "Numeric" to "NumericLiteral".

Norm / rule (3|4)
"return then"
    Delete "then".

Norm / rule (3|6)
$fs:last - Numeric + 1
$fs:last - $fs:new + 1
    Plus and minus operators are not in the Core language. Change to:
       fs:plus( 1, fs:minus( $fs:last, NumericLiteral ) )
       fs:plus( 1, fs:minus( $fs:last, $fs:new ) )

Norm / rule (5|6)
"if [[ Expr ]]_Predicates then"
    Put IfExpr's condition in parentheses.

STA
"Axis"
    There's no definition for the symbol 'Axis'.

DEv / rule 1 / premise 2
"Value1 matches node"
    'node' is not a valid (Formal) Type.
    In STA / rule 1, you changed 'node' to
        [[ node() ]]_sequencetype
    so you probably need to do that here too.
(leftover from last year, comment #058)
Received on Thursday, 14 July 2005 06:01:26 UTC

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