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RDF-to-Functional mapping: What happens if an RDF graph contains un-mappable portions?

From: Michael Schneider <schneid@fzi.de>
Date: Fri, 14 Mar 2008 14:16:33 +0100
Message-ID: <0EF30CAA69519C4CB91D01481AEA06A0803297@judith.fzi.de>
To: "OWL Working Group WG" <public-owl-wg@w3.org>
[related to ISSUE-89]


I just found myself unable to answer the following question: Given an RDF
graph, which contains portions for which there is no RDF-to-Functional
transformation. Is this RDF graph syntactically in-valid w.r.t. OWL-1.1-DL?

The background of my question is what happens to old OWL-1.0-DL ontologies
in RDF syntax, which contain entities for which there is only a typing
triple. For example, for the RDF graph

  G := { t1 } 


  t1 := "ex:C rdf:type owl:Class"

there is no mapping for the triple t1. So does this mean that the graph G as
a /whole/ cannot be mapped to Functional Syntax? Or does this rather mean
that the triple t1 is silently ignored by the mapping, and the remaining RDF
graph G* := {} is mapped to Functional Syntax? If the latter is true, would
then G as a whole still be called a syntactically valid OWL-1.1-DL ontology?


Dipl.-Inform. Michael Schneider
FZI Forschungszentrum Informatik Karlsruhe
Abtl. Information Process Engineering (IPE)
Tel  : +49-721-9654-726
Fax  : +49-721-9654-727
Email: Michael.Schneider@fzi.de
Web  : http://www.fzi.de/ipe/eng/mitarbeiter.php?id=555

FZI Forschungszentrum Informatik an der Universität Karlsruhe
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Received on Friday, 14 March 2008 13:17:13 UTC

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