RDF-to-Functional mapping: What happens if an RDF graph contains un-mappable portions?

[related to ISSUE-89]

Hi!

I just found myself unable to answer the following question: Given an RDF
graph, which contains portions for which there is no RDF-to-Functional
transformation. Is this RDF graph syntactically in-valid w.r.t. OWL-1.1-DL?

The background of my question is what happens to old OWL-1.0-DL ontologies
in RDF syntax, which contain entities for which there is only a typing
triple. For example, for the RDF graph

  G := { t1 } 

with

  t1 := "ex:C rdf:type owl:Class"

there is no mapping for the triple t1. So does this mean that the graph G as
a /whole/ cannot be mapped to Functional Syntax? Or does this rather mean
that the triple t1 is silently ignored by the mapping, and the remaining RDF
graph G* := {} is mapped to Functional Syntax? If the latter is true, would
then G as a whole still be called a syntactically valid OWL-1.1-DL ontology?

Cheers,
Michael

--
Dipl.-Inform. Michael Schneider
FZI Forschungszentrum Informatik Karlsruhe
Abtl. Information Process Engineering (IPE)
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Email: Michael.Schneider@fzi.de
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