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RE: ISSUE-101 (plainliterals): equating plain literals with no language tag to xsd:string

From: Michael Schneider <schneid@fzi.de>
Date: Fri, 14 Mar 2008 11:23:19 +0100
Message-ID: <0EF30CAA69519C4CB91D01481AEA06A0803269@judith.fzi.de>
To: "OWL Working Group WG" <public-owl-wg@w3.org>
Oops, this time it was me who overlooked a newly raised issue... by Alan. :) 

>ISSUE-101 (plainliterals): equating plain literals with no 
>language tag to xsd:string
>
>http://www.w3.org/2007/OWL/tracker/issues/
>
>Raised by: Alan Ruttenberg
>On product: 
>
>RDF specifies that plain literals with no language tags are to 
>be equated with xsd:strings. 

Hm, can someone tell me where RDF does specify this? 

Perhaps I misunderstand this issue, but I thought it was a well known fact that xsd:string builds a separate datatype from the plain literals (with or without a language tags), and that there is no defined way to compare elements from both sets.

What I can find is that the RDF Concepts spec says in [1]:

    Two literals are equal if and only if all of the following hold:

        * The strings of the two lexical forms compare equal, character by character.
        * Either both or neither have language tags.
        * The language tags, if any, compare equal.
    [!] * Either both or neither have datatype URIs.
        * The two datatype URIs, if any, compare equal, character by character.

>RIF makes the same choice. I think we should too.

Provided that I have understood the issue, I disagree. In this case the main premise of this issue is wrong, so I would rather opt to reject this issue.

Michael

[1] <http://www.w3.org/TR/2004/REC-rdf-concepts-20040210/#section-Literal-Equality>

--
Dipl.-Inform. Michael Schneider
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Abtl. Information Process Engineering (IPE)
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Received on Friday, 14 March 2008 10:23:57 GMT

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