Re: SKOS transitive hierarchical relations

On Jan 4, 2012, at 6:09 PM, Antoine Isaac wrote:

> Dear Dominique,
> 
>> 
>> Le 4 janv. 2012 à 15:26, Antoine Isaac a écrit :
>> 
>> I'm currently developing a little thesaurus management web application, this point is important for me too
>> 
>>> Indeed, the original idea is that the vocabulary providers would start publish assertions with skos:broader/narrower.
>> 
>> Who do you call the "vocabulary providers" ?
> 
> 
> Sorry, "publisher of SKOS data" is maybe clearer.
> 
> 
>> If I'm creating a SKOS thesaurus from scratch, using a web GUI that allows me to state either kind of relation, and I know that two concepts have a broaderTransitive relation, what prevents me in the SKOS specification to qualify this relation directly as broaderTransitive ?
> 
> 
> Well, nothing prevents you from doing that, but then you have lost some information. Despite the property names, asserting a skos:broader is indeed *more precise* than asserting a skos:broaderTransitive. Because the former implies the latter (mathematically speaking, the skos:broaderTransitive is the transitive closure of the skos:broader relation, http://en.wikipedia.org/wiki/Transitive_closure)

Not quite. The definitions give us that skos:broaderTransitive _includes_ the transitive closure of skos:broader, but it's not an equivalence. 

	Sean

--
Sean Bechhofer
School of Computer Science
University of Manchester
sean.bechhofer@manchester.ac.uk
http://www.cs.manchester.ac.uk/~seanb

Received on Friday, 6 January 2012 14:48:18 UTC